let α, β are roots of quadratic equation ax^2 + bx + c = 0, if a,b,c are in GP and αβ = 9, the possible value of |α+ β| is
S1 : For ax^2 + bx + c = 0 (a ≠ 0) if a + b + c = 0, then the roots are 1 and c/a S2 : If f(x) = ax^2 + bx + c (a ≠ 0) - Sarthaks eConnect | Largest Online Education Community
What is the least value of the function ax^2+bx+c for a>0 and a<0? Provide explanation. Use both the methods in the description. - Quora
![if a b c are positive real numbers prove that both the roots of ax 2 bx c 0 have negative real parts g99awsff -Maths - TopperLearning.com if a b c are positive real numbers prove that both the roots of ax 2 bx c 0 have negative real parts g99awsff -Maths - TopperLearning.com](https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=c9691dea37c9fc4d8cdbbf7c76e744cc.png&d=0)
if a b c are positive real numbers prove that both the roots of ax 2 bx c 0 have negative real parts g99awsff -Maths - TopperLearning.com
![Write the Following Equations in the Form Ax2 + Bx + C= 0, Then Write the Values of A, B, C for Each - Brainly.in Write the Following Equations in the Form Ax2 + Bx + C= 0, Then Write the Values of A, B, C for Each - Brainly.in](https://hi-static.z-dn.net/files/dfb/e20f9e35ca0f7b331a86f19dc7b6eb04.jpg)
Write the Following Equations in the Form Ax2 + Bx + C= 0, Then Write the Values of A, B, C for Each - Brainly.in
![If one root of the quadratic equation ax2 + bx + c = 0 is the square of the other - Maths - - 12051821 | Meritnation.com If one root of the quadratic equation ax2 + bx + c = 0 is the square of the other - Maths - - 12051821 | Meritnation.com](https://img-nm.mnimgs.com/img/study_content/content_ck_images/images/1(1009).png)
If one root of the quadratic equation ax2 + bx + c = 0 is the square of the other - Maths - - 12051821 | Meritnation.com
If the sum of coefficient of ax^2+bx+c=0 is zero (ie. a+b+c=0) then the roots of the equation are: (a) 1 b/a (b) 1 c/a (c) 0 c/a (d) 1
![If p(x) = ax2+ bx + c and a + b + c = 0, then onezero isa)-b/ab)c/ac)b/cd)none of theseCorrect answer is option 'B'. Can you explain this answer? | EduRev Class If p(x) = ax2+ bx + c and a + b + c = 0, then onezero isa)-b/ab)c/ac)b/cd)none of theseCorrect answer is option 'B'. Can you explain this answer? | EduRev Class](https://edurev.gumlet.io/ApplicationImages/Temp/e237cbbb-2ea0-4249-8aab-305d9f34790f_lg.jpg?w=360&dpr=2.6)
If p(x) = ax2+ bx + c and a + b + c = 0, then onezero isa)-b/ab)c/ac)b/cd)none of theseCorrect answer is option 'B'. Can you explain this answer? | EduRev Class
![SOLVED: 16 Question (3 Points) The quadratic equation ax2 +bx + c = 0 has no solution if b2 4ac = 0 True False SOLVED: 16 Question (3 Points) The quadratic equation ax2 +bx + c = 0 has no solution if b2 4ac = 0 True False](https://cdn.numerade.com/ask_images/9513a7eac35144e1a34479119893e8de.jpg)
SOLVED: 16 Question (3 Points) The quadratic equation ax2 +bx + c = 0 has no solution if b2 4ac = 0 True False
If the roots of ax^2 +bx+c=0 differ by 1, how do you show that they are (a-b) /2a and (-a+b/2a) and prove that b^2=a (a+4c)? - Quora
![In quadratic equation ax^(2)+bx+c=0, if discriminant D=b^(2)-4ac, then roots of quadratic equation are: In quadratic equation ax^(2)+bx+c=0, if discriminant D=b^(2)-4ac, then roots of quadratic equation are:](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/15088149_web.png)
In quadratic equation ax^(2)+bx+c=0, if discriminant D=b^(2)-4ac, then roots of quadratic equation are:
![Solve the quadratic equation ax2 + bx + c = 0, by method of completing the perfect square. - Brainly.in Solve the quadratic equation ax2 + bx + c = 0, by method of completing the perfect square. - Brainly.in](https://hi-static.z-dn.net/files/d14/a0c1672b3414943f9b392bb2fa3c30d2.jpg)
Solve the quadratic equation ax2 + bx + c = 0, by method of completing the perfect square. - Brainly.in
![If both the roots of $a{x^2} + bx + c = 0$ are negative, then ${\\text{A}}{\\text{. }}\\Delta {\\text{ 0,ab 0,bc 0}} \\\\{\\text{B}}{\\text{. }}\\Delta {\\text{ 0,a,b,c,have same sign}} \\\\{\\text{C}}{\\text{. }}\\Delta {\\text{ 0,ab 0,ac If both the roots of $a{x^2} + bx + c = 0$ are negative, then ${\\text{A}}{\\text{. }}\\Delta {\\text{ 0,ab 0,bc 0}} \\\\{\\text{B}}{\\text{. }}\\Delta {\\text{ 0,a,b,c,have same sign}} \\\\{\\text{C}}{\\text{. }}\\Delta {\\text{ 0,ab 0,ac](https://www.vedantu.com/question-sets/be509327-f9cc-406a-979a-65c26c9dab1c5518764430088251940.png)